1/x^2+8/x-3

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Solution for 1/x^2+8/x-3 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

8/x+1/(x^2)-3 = 0

8*x^-1+x^-2-3 = 0

t_1 = x^-1

1*t_1^2+8*t_1^1-3 = 0

t_1^2+8*t_1-3 = 0

DELTA = 8^2-(-3*1*4)

DELTA = 76

DELTA > 0

t_1 = (76^(1/2)-8)/(1*2) or t_1 = (-76^(1/2)-8)/(1*2)

t_1 = (2*19^(1/2)-8)/2 or t_1 = (-2*19^(1/2)-8)/2

t_1 = (-2*19^(1/2)-8)/2

x^-1-((-2*19^(1/2)-8)/2) = 0

1*x^-1 = (-2*19^(1/2)-8)/2 // : 1

x^-1 = (-2*19^(1/2)-8)/2

-1 < 0

1/(x^1) = (-2*19^(1/2)-8)/2 // * x^1

1 = ((-2*19^(1/2)-8)/2)*x^1 // : (-2*19^(1/2)-8)/2

2*(-2*19^(1/2)-8)^-1 = x^1

x = 2*(-2*19^(1/2)-8)^-1

t_1 = (2*19^(1/2)-8)/2

x^-1-((2*19^(1/2)-8)/2) = 0

1*x^-1 = (2*19^(1/2)-8)/2 // : 1

x^-1 = (2*19^(1/2)-8)/2

-1 < 0

1/(x^1) = (2*19^(1/2)-8)/2 // * x^1

1 = ((2*19^(1/2)-8)/2)*x^1 // : (2*19^(1/2)-8)/2

2*(2*19^(1/2)-8)^-1 = x^1

x = 2*(2*19^(1/2)-8)^-1

x in { 2*(-2*19^(1/2)-8)^-1, 2*(2*19^(1/2)-8)^-1 }

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